\(k_x = \frac{k_1.h_1 + k_2.h_2}{h_1 + h_2}\)
\(k_x = \frac{k_1+K_2}2\)
\(k_x = \frac{k_1.h_3 + k_2.h_2}{h_1 + h_2}\)
\(k_x = \sqrt{k_1.k_2}\)
Step 1: Equivalent horizontal hydraulic conductivity. When flow is parallel to the stratification, the equivalent horizontal hydraulic conductivity \( K_x \) for the aquifer system is given by: \[ K_x = \frac{\sum (K_i \cdot h_i)}{\sum h_i} \] where \( K_i \) and \( h_i \) are the hydraulic conductivity and thickness of the \( i \)-th layer, respectively.
Step 2: Substitute for two layers. For two layers, the equation becomes: \[ K_x = \frac{K_1 h_1 + K_2 h_2}{h_1 + h_2} \]
Step 3: Interpretation of the terms. \( K_1 h_1 \): Contribution of layer-1 to the equivalent hydraulic conductivity. \( K_2 h_2 \): Contribution of layer-2 to the equivalent hydraulic conductivity. \( h_1 + h_2 \): Total thickness of the aquifer system.
Step 4: Verify the given options. The correct formula for equivalent horizontal conductivity matches: \[ K_x = \frac{K_1 h_1 + K_2 h_2}{h_1 + h_2} \]