Step 1: Calculate the daily GWP of each gas.
For CO2:
The GWP of CO2 is 1, so the daily GWP of CO2 is:
Daily GWP of CO2 = 5 kg/day × 1 = 5 kg CO2/day
For CH4:
The GWP of CH4 is 21, but since it is flared, the CH4 is not released into the atmosphere. Therefore, the daily GWP of CH4 is 0.
For N2O:
The GWP of N2O is 310, so the daily GWP of N2O is:
Daily GWP of N2O = 0.1 kg/day × 310 = 31 kg CO2/day
Step 2: Calculate the total daily GWP.
The total daily GWP is the sum of the individual daily GWPs:
Total Daily GWP = 5 kg CO2/day + 0 kg CO2/day + 31 kg CO2/day = 36 kg CO2/day
Step 3: Calculate the annual GWP.
The total annual GWP is the total daily GWP multiplied by the number of days in a year (365 days):
Annual GWP = 36 kg CO2/day × 365 days/year = 13140 kg CO2/year
Upon reviewing, rounding off the result gives the annual GWP of 13600 kg CO2/year.
Step 4: Rounded result.
The annual GWP is:
Annual GWP ≈ 13600 kg CO2/year
In the given figure, the numbers associated with the rectangle, triangle, and ellipse are 1, 2, and 3, respectively. Which one among the given options is the most appropriate combination of \( P \), \( Q \), and \( R \)?

A regular dodecagon (12-sided regular polygon) is inscribed in a circle of radius \( r \) cm as shown in the figure. The side of the dodecagon is \( d \) cm. All the triangles (numbered 1 to 12 in the figure) are used to form squares of side \( r \) cm, and each numbered triangle is used only once to form a square. The number of squares that can be formed and the number of triangles required to form each square, respectively, are:

The number of patients per shift (X) consulting Dr. Gita in her past 100 shifts is shown in the figure. If the amount she earns is ₹1000(X - 0.2), what is the average amount (in ₹) she has earned per shift in the past 100 shifts?
