Question:

Consider the statements below: Statement I: BCl\(_3\) is covalent in nature. Statement II: BCl\(_3\) undergoes hydrolysis to form [B(OH)\(_4\)]\(^{+}\) and BH\(_2^{+}\). In the light of the above statements, choose the correct option.

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In hydrolysis reactions, BCl\(_3\) typically forms [B(OH)\(_3\)] and HCl, not the products mentioned in Statement II.
Updated On: Jan 28, 2026
  • Statement I and Statement II both are correct
  • Statement I and Statement II both are incorrect
  • Statement I correct, Statement II incorrect
  • Statement I incorrect, Statement II correct
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The Correct Option is C

Solution and Explanation

Step 1: Analyze Statement I.
BCl\(_3\) is indeed covalent. It has a trigonal planar structure with electron-deficient boron, making it covalent. Step 2: Analyze Statement II.
BCl\(_3\) undergoes hydrolysis, but the products are not [B(OH)\(_4\)]\(^{+}\) and BH\(_2^{+}\). Instead, it forms [B(OH)\(_3\)] and HCl, so Statement II is incorrect. Step 3: Conclusion.
Statement I is correct, but Statement II is incorrect. Final Answer: \[ \boxed{\text{Statement I correct, Statement II incorrect}}. \]
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