Question:

Consider the set S = 1, 2, 3, …, 10001. How many arithmetic progressions with at least 3 elements can be formed from the elements of S that start with 1 and end with 1000?

Updated On: Jul 24, 2024
  • 6
  • 7
  • 8
  • 12
  • 13
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The Correct Option is B

Solution and Explanation

The correct option is (B): 7
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