Question:

Consider the sequence of oxides : $Na _{2} O , SiO _{2}$, $P _{4} O _{10}$. Which factor decreases from $Na _{2} O$ to $SiO _{2}$ and also from $SiO _{2}$ to $P _{4} O _{10}$ ?

Updated On: Jul 2, 2022
  • Covalent character
  • Melting point
  • pH when mixed with water
  • Solubility in aqueous alkali
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The Correct Option is C

Solution and Explanation

$Na _{2} O$ is a basic oxide and reacts with water to give $NaOH$ so that its $pH$ is higher than both $SiO _{2}$ and $P _{4} O _{10}$. Both $SiO _{2}$ and $P _{4} O _{10}$ are acidic oxides but $SiO _{2}$ is insoluble while $P_{4} O_{10}$ reacts with water to give $H _{3} PO _{4}$. Thus, for $P _{4} O _{10}, pH$ when mixed with water is lower than that of $SiO _{2}$.
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Concepts Used:

P-Block Elements

  • P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
  • P block elements are shiny and usually a good conductor of electricity and heat as they have a tendency to lose an electron. You will find some amazing properties of elements in a P-block element like gallium. It’s a metal that can melt in the palm of your hand. Silicon is also one of the most important metalloids of the p-block group as it is an important component of glass.

P block elements consist of: