Question

Consider the reaction:VO + Fe2O3 → FeO + V2O5Calculate the weight of FeO produced from 2 g of VO and 5.75 g of Fe2O3.[Take atomic weights of V and Fe to be 51 u and 56 u, respectively.]

• (A) 5.17 g
• (B) 5.75 g
• (C) 6.76 g
• (D) 7.19 g

Answer 1

The Correct Option is A

Explanation:
Balanced equation:$$2\mathrm{VO}+3{\mathrm{Fe}}_2{\mathrm{O}}_3\to 6\mathrm{FeO}+{\mathrm{V}}_2{\mathrm{O}}_5$$Moles before reaction: $n_{VO}=\frac{2}{67}=0.0298$$$n_{F{e}_2{O}_3}=\frac{5.75}{160}=0.0359$$Amount of ${\mathrm{Fe}}_2{\mathrm{O}}_3$ required by $0.0298\mathrm{g}$ of $\mathrm{VO}=\frac{3}{2}\times 0.0298=0.0447$8Therefore, ${\mathrm{Fe}}_2{\mathrm{O}}_3$ is the limiting reagent.$$n_{\text{FeO}}\text{formed}=2\times n_{F{e}_2}{O}_3\text{used}=2\times 0.0359=0.0718$$Weight of FeO produced $=0.0718\times 72=5.169\mathrm{g}$