Consider the parabola $y^2=4 x$ Let $S$ be the focus of the parabola A pair of tangents drawn to the parabola from the point $P=(-2,1)$ meet the parabola at $P_1$ and $P_2$ Let $Q_1$ and $Q_2$ be points on the lines $S P_1$ and $S P_2$ respectively such that $P Q_1$ is perpendicular to $S P_1$ and $P Q_2$ is perpendicular to $S P_2$ Then, which of the following is/are TRUE ?
- $S Q_l=2$
- $Q _1 Q _2=\frac{3 \sqrt{10}}{5}$
- $PQ _1=3$
- $SQ _2=1$
The Correct Option is D
Solution and Explanation
D
$SQ _2=1$
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