To determine the nature of the critical points, we first compute the first-order partial derivatives of \( f(x, y) \): \[ f_x = 2xy + 2y^2 - 4xy^2, f_y = x^2 + 4xy - 4x^2y. \] Next, we set both \( f_x = 0 \) and \( f_y = 0 \) to find the critical points. After solving the system of equations, we find the critical point at \( \left( \frac{3}{2}, \frac{3}{4} \right) \).
Now, we calculate the second-order partial derivatives: \[ f_{xx} = 2y - 4y^2, f_{yy} = 4x - 4x^2, f_{xy} = 4y - 8xy. \] At the critical point \( \left( \frac{3}{2}, \frac{3}{4} \right) \), we compute the discriminant \( D = f_{xx} f_{yy} - (f_{xy})^2 \). After evaluating, we find that \( D<0 \), which indicates that the critical point is a saddle point. Thus, \( \left( \frac{3}{2}, \frac{3}{4} \right) \) is a saddle point of \( f \).
Let \( f: \mathbb{R} \times \mathbb{R} \to \mathbb{R} \) be defined as:
\[ f(x, y) = \begin{cases} \frac{x}{\sqrt{x^2 + y^2}} & \text{if } (x, y) \neq (0, 0) \\ 1 & \text{if } (x, y) = (0, 0) \end{cases} \] Then, which of the following statements is true?