Question:

Consider the fully-developed flow of a Newtonian fluid (density \( \rho \); viscosity \( \mu \)) through a smooth pipe of diameter \( D \) and length \( L \). The average velocity of the flow is \( V \). If the length of the pipe is doubled, keeping \( V \), \( D \), \( \rho \), \( \mu \) constant, the friction factor

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The friction factor in fully-developed flow through a smooth pipe does not depend on the pipe length, but rather on the Reynolds number and the pipe roughness.
Updated On: Jan 6, 2026
  • increases by two times
  • remains the same
  • decreases by two times
  • increases four times
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The Correct Option is B

Solution and Explanation

For fully-developed flow in a smooth pipe, the friction factor \( f \) depends on the Reynolds number and is independent of the pipe length. The Darcy-Weisbach equation describes the pressure drop in a pipe as: \[ \Delta P = f \frac{L}{D} \frac{\rho V^2}{2} \] Here, the friction factor \( f \) is related to the flow characteristics (like Reynolds number), but it does not depend on the length of the pipe \( L \). Since all other variables are held constant, doubling the pipe length \( L \) will not change the friction factor. Therefore, the friction factor remains the same. The correct answer is (B).
Final Answer: (B) remains the same
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