Consider the following Statements [1] and [2].
Statement [1]: The Eulerian study focuses attention on individual particle and its motion is observed as a function of time.
Statement [2]: The Lagrangian study focuses attention on the motion of the particles passing through an identified point.
Which one of the following options identifies the correctness of the given statements?
The Eulerian and Lagrangian methods are two fundamental approaches in fluid mechanics for describing the motion of fluid particles.
- Eulerian Method: This method focuses on observing the fluid at fixed points in space. In other words, the Eulerian study looks at the velocity field at specific locations, as a function of time. It does not track individual particles; rather, it focuses on how the flow characteristics change at fixed points in space.
Therefore, Statement [1] is incorrect, because it wrongly describes the Eulerian study as focusing on individual particles and their motion as a function of time.
- Lagrangian Method: The Lagrangian study, on the other hand, follows individual fluid particles as they move through space. This method tracks the motion of particles from a fixed perspective, which means it looks at the movement of fluid particles as they pass through identified points. Therefore, Statement [2] is also incorrect, as it wrongly describes the Lagrangian method as focusing on the motion of particles passing through a specific point, which is not its primary focus. The Lagrangian approach follows individual particles along their entire path, rather than observing the flow at fixed points.
Thus, the correct answer is (B) Both [1] and [2] are NOT correct.
Consider two identical tanks with a bottom hole of diameter \( d \). One tank is filled with water and the other tank is filled with engine oil. The height of the fluid column \( h \) is the same in both cases. The fluid exit velocity in the two tanks are \( V_1 \) and \( V_2 \). Neglecting all losses, which one of the following options is correct?

A pitot tube connected to a U-tube mercury manometer measures the speed of air flowing in the wind tunnel as shown in the figure below. The density of air is 1.23 kg m\(^{-3}\) while the density of water is 1000 kg m\(^{-3}\). For the manometer reading of \( h = 30 \) mm of mercury, the speed of air in the wind tunnel is _________ m s\(^{-1}\) (rounded off to 1 decimal place).

Consider a velocity field \( \vec{V} = 3z \hat{i} + 0 \hat{j} + Cx \hat{k} \), where \( C \) is a constant. If the flow is irrotational, the value of \( C \) is (rounded off to 1 decimal place).