Consider the following sequence of reactions: i) $ \text{Mg}, \text{dry ether} $ ii) $ \text{CO}_2, \text{H}_2\text{O}^+ $ iii) $ \text{NH}_3, \Delta $ 11.25 mg of chlorobenzene will produce $ x \times 10^{-1} $ mg of product B. Given molar mass of C, H, O, N, and Cl as 12, 1, 16, 14, and 35.5 g mol$^{-1}$, respectively, the value of $ x $ is:

Question

Consider the following sequence of reactions:   i) $ \text{Mg}, \text{dry ether} $   ii) $ \text{CO}_2, \text{H}_2\text{O}^+ $  iii) $ \text{NH}_3, \Delta $  11.25 mg of chlorobenzene will produce $ x \times 10^{-1} $ mg of product B. Given molar mass of C, H, O, N, and Cl as 12, 1, 16, 14, and 35.5 g mol$^{-1}$, respectively, the value of $ x $ is:

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Step 1: Determine the moles of chlorobenzene. $$ \text{Moles of chlorobenzene} = \frac{11.25 \, \text{mg}}{1 \, \text{g/mol}} = \frac{11.25 \times 10^{-3}}{C_6H_5Cl} $$ Step 2: Calculate the corresponding amount of product B after completing the reaction. Final Conclusion: The value of $ x $ is 9.

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Correct Answer: 9

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