We are given the equilibrium concentrations of N2, O2, and NO, and asked to find the degree of dissociation (α) of NO.
The dissociation of NO follows the reaction:
2NO(g) ⇌ N2(g) + O2(g)
Since the concentration of N2 is equal to α, we can set up the following equation:
α = 3.0 × 10−3 M
Similarly, the concentration of O2 is also equal to α, which gives:
α = 4.2 × 10−3 M
Using the initial concentration of NO (0.1 M), we can solve for α:
α = 3.0 × 10−3 / 0.1 = 0.03
The degree of dissociation is approximately 0.717.
An ideal massless spring \( S \) can be compressed \( 1 \) m by a force of \( 100 \) N in equilibrium. The same spring is placed at the bottom of a frictionless inclined plane inclined at \( 30^\circ \) to the horizontal. A \( 10 \) kg block \( M \) is released from rest at the top of the incline and is brought to rest momentarily after compressing the spring by \( 2 \) m. If \( g = 10 \) m/s\( ^2 \), what is the speed of the mass just before it touches the spring?
List I | List II | ||
A | Down’s syndrome | I | 11th chormosome |
B | α-Thalassemia | II | ‘X’ chromosome |
C | β-Thalassemia | III | 21st chromosome |
D | Klinefelter’s syndrome | IV | 16th chromosome |
The velocity (v) - time (t) plot of the motion of a body is shown below :
The acceleration (a) - time(t) graph that best suits this motion is :