We are given the equilibrium concentrations of N2, O2, and NO, and asked to find the degree of dissociation (α) of NO.
The dissociation of NO follows the reaction:
2NO(g) ⇌ N2(g) + O2(g)
Since the concentration of N2 is equal to α, we can set up the following equation:
α = 3.0 × 10−3 M
Similarly, the concentration of O2 is also equal to α, which gives:
α = 4.2 × 10−3 M
Using the initial concentration of NO (0.1 M), we can solve for α:
α = 3.0 × 10−3 / 0.1 = 0.03
The degree of dissociation is approximately 0.717.
An ideal massless spring \( S \) can be compressed \( 1 \) m by a force of \( 100 \) N in equilibrium. The same spring is placed at the bottom of a frictionless inclined plane inclined at \( 30^\circ \) to the horizontal. A \( 10 \) kg block \( M \) is released from rest at the top of the incline and is brought to rest momentarily after compressing the spring by \( 2 \) m. If \( g = 10 \) m/s\( ^2 \), what is the speed of the mass just before it touches the spring?
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R.
Assertion A : The potential (V) at any axial point, at 2 m distance(r) from the centre of the dipole of dipole moment vector
\(\vec{P}\) of magnitude, 4 × 10-6 C m, is ± 9 × 103 V.
(Take \(\frac{1}{4\pi\epsilon_0}=9\times10^9\) SI units)
Reason R : \(V=±\frac{2P}{4\pi \epsilon_0r^2}\), where r is the distance of any axial point, situated at 2 m from the centre of the dipole.
In the light of the above statements, choose the correct answer from the options given below :
The output (Y) of the given logic gate is similar to the output of an/a :