Question:

Consider the following reaction:
Identify A and B
Identify A and B from the given options:

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In decarboxylation reactions, heating in the presence of a strong base often results in the formation of alcohols and formates.
Updated On: Feb 25, 2025
  • A — Methanol, B — Potassium formate
  • A — Ethanol, B — Potassium formate
  • A — Methanal, B — Ethanol
  • A — Methanol, B — Potassium acetate
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The Correct Option is A

Solution and Explanation

The reaction described is a typical decarboxylation reaction where formic acid (\( \text{HCOOH} \)) undergoes reduction in the presence of concentrated KOH. When heated, formic acid decarboxylates, resulting in methanol (CH$_3$OH) and potassium formate (HCOOK). The reaction proceeds as follows:
1. The formic acid is treated with concentrated KOH.
2. The hydroxide ion attacks the carbonyl group of the formic acid, leading to the formation of potassium formate and the liberation of carbon dioxide.
3. The remaining product after decarboxylation is methanol.
Decarboxylation of formic acid yields methanol and potassium formate.
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