Step 1: Identifying the Coding Sequence: The given sequence contains the start codon (AUG) and a termination codon (UAA). The coding sequence starts at AUG and ends at UAA.
Step 2: Calculating the Number of Codons: The sequence from the start codon AUG to the termination codon UAA is: AUGGCGUCGCUACGUCGCGCUCACGCGGACGAUCGUACGUA This sequence contains 14 codons.
Step 3: Calculating the Molecular Mass: Given that each amino acid has an average molecular mass of 110 daltons and recognizing that the termination codon does not contribute to the amino acid count, the calculation is as follows: [ {Number of amino acids} times 110 , {daltons/amino acid} = 14 times 110 ]
Result: [ {Total molecular mass} = 1540 , {daltons} ] Conclusion:
Explanation: The translation of the nucleotide sequence results in a polypeptide of 14 amino acids. Given the average mass of an amino acid, the total mass of the polypeptide is calculated as 1540 daltons.
The \( F_{121} \) value of a known microorganism with \( Z \) value of \( 11^\circ C \) is 2.4 min for 99.9999% inactivation. For a 12D inactivation of the said microorganism at \( 143^\circ C \), the \( F \) value (in min) is .......... (rounded off to 3 decimal places)
Three villages P, Q, and R are located in such a way that the distance PQ = 13 km, QR = 14 km, and RP = 15 km, as shown in the figure. A straight road joins Q and R. It is proposed to connect P to this road QR by constructing another road. What is the minimum possible length (in km) of this connecting road?
Note: The figure shown is representative.
For the clock shown in the figure, if
O = O Q S Z P R T, and
X = X Z P W Y O Q,
then which one among the given options is most appropriate for P?