We are given four straight lines. To determine the correct relationship between the lines, we need to calculate the slopes of the lines and then compare them.
Step 1: Find the slope of each line.
- The equation of line L1 is \( 2x - 3y = 5 \). Rewriting it in slope-intercept form \( y = mx + c \), we get:
\[ 3y = 2x - 5 \quad \Rightarrow \quad y = \frac{2}{3}x - \frac{5}{3} \quad \text{(Slope of L1 is } \frac{2}{3} \text{)} \]
- The equation of line L2 is \( 3x + 2y = 8 \). Rewriting it:
\[ 2y = -3x + 8 \quad \Rightarrow \quad y = -\frac{3}{2}x + 4 \quad \text{(Slope of L2 is } -\frac{3}{2} \text{)} \]
- The equation of line L3 is \( 4x - 6y = 5 \). Rewriting it:
\[ 6y = 4x - 5 \quad \Rightarrow \quad y = \frac{2}{3}x - \frac{5}{6} \quad \text{(Slope of L3 is } \frac{2}{3} \text{)} \]
- The equation of line L4 is \( 6x - 9y = 6 \). Rewriting it:
\[ 9y = 6x - 6 \quad \Rightarrow \quad y = \frac{2}{3}x - \frac{2}{3} \quad \text{(Slope of L4 is } \frac{2}{3} \text{)} \]
Step 2: Analyze the relationships.
- Lines L1, L3, and L4 have the same slope of \( \frac{2}{3} \), so they are parallel.
- Line L2 has a slope of \( -\frac{3}{2} \), which is different from the other lines, indicating that it is neither parallel nor perpendicular to L1, L3, or L4.
- Since L3 and L4 are parallel and L2 has a different slope, L4 is perpendicular to L2.
Thus, the correct statement is (D).