Question:

Consider the following cases:
(a) CaSO4 + Al →
(b) CuSO4 + Ca →
(c) FeSO4 + Cu →
(d) ZnSO4 + Mg →
The cases in which new products will form are –

Updated On: Jun 10, 2025
  • (a) and (b)
  • (b) and (c)
  • (c) and (d)
  • (b) and (d)
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The Correct Option is D

Solution and Explanation

Step 1: Understanding the reactions:
The question presents different reactions involving a metal and a metal salt. We need to determine which reactions will result in the formation of new products. This can be determined by comparing the reactivity of the metals involved, as more reactive metals can displace less reactive metals from their salts.

Case (a): CaSO4 + Al
This reaction will not occur. Calcium sulfate (CaSO4) is a very stable compound, and aluminum (Al) is not reactive enough to displace calcium from calcium sulfate. Therefore, no new products will form in this case.

Case (b): CuSO4 + Ca
Calcium (Ca) is more reactive than copper (Cu). It can displace copper from copper sulfate (CuSO4) and form calcium sulfate (CaSO4) and copper (Cu) as new products. Therefore, new products will form in this case.

Case (c): FeSO4 + Cu
Copper (Cu) is less reactive than iron (Fe). Copper will not be able to displace iron from iron sulfate (FeSO4). Therefore, no new products will form in this case.

Case (d): ZnSO4 + Mg
Magnesium (Mg) is more reactive than zinc (Zn). It can displace zinc from zinc sulfate (ZnSO4) and form magnesium sulfate (MgSO4) and zinc (Zn) as new products. Therefore, new products will form in this case.

Step 2: Conclusion:
The cases in which new products will form are (b) and (d).
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