The reduction potential for the given electrodes can be calculated using the Nernst equation: \[ E = E^\circ - \frac{0.0591}{n} \log \left( \frac{[\text{Reductant}]}{[\text{Oxidant}]} \right) \] Since the number of electrons involved in the silver (Ag) reduction reaction is 1 (i.e., \( n = 1 \)), the equation simplifies to: \[ E = E^\circ - 0.0591 \log [\text{Ag}^+] \] The standard reduction potential \( E^\circ_{\text{Ag}^+/\text{Ag}} \) is given as +0.80 V for standard conditions.
Using the Nernst equation: - For electrode A: \[ E_A = 0.80 - 0.0591 \log (0.0001) = 0.80 - 0.0591 \times (-4) = 0.80 + 0.2364 = 1.0364 \text{ V} \] - For electrode B: \[ E_B = 0.80 - 0.0591 \log (0.1) = 0.80 - 0.0591 \times (-1) = 0.80 + 0.0591 = 0.8591 \text{ V} \] - For electrode C: \[ E_C = 0.80 - 0.0591 \log (0.01) = 0.80 - 0.0591 \times (-2) = 0.80 + 0.1182 = 0.9182 \text{ V} \] - For electrode D: \[ E_D = 0.80 - 0.0591 \log (0.001) = 0.80 - 0.0591 \times (-3) = 0.80 + 0.1773 = 0.9773 \text{ V} \]
The reduction potentials for the electrodes in descending order are: \[ \text{B} > \text{C} > \text{D} > \text{A} \] Therefore, the correct order is Option (A): B > C > D > A.
Correct Answer: Option (A)
The reduction potential depends on the concentration of the ions. The Nernst equation is used to calculate the electrode potential: \[ E = E^\circ - \frac{0.0591}{n} \log \left(\frac{[Ag^+]}{[Ag]}\right) \] where:
\( E^\circ \) is the standard reduction potential,
\( [Ag^+] \) is the concentration of the silver ion,
\( [Ag] \) is the concentration of solid silver, and
\( n = 1 \) (for the silver electrode, as it involves the reduction of one electron).
For the given electrodes:
A has the lowest concentration of Ag⁺ (0.0001 M), so it will have the lowest reduction potential.
B has the highest concentration of Ag⁺ (0.1 M), so it will have the highest reduction potential.
C and D have intermediate values, with C being greater than B in terms of concentration and hence its reduction potential.
Therefore, the order of reduction potentials is B > C > D > A.
In the above diagram, the standard electrode potentials are given in volts (over the arrow). The value of \( E^\circ_{\text{FeO}_4^{2-}/\text{Fe}^{2+}} \) is:
The elements of the 3d transition series are given as: Sc, Ti, V, Cr, Mn, Fe, Co, Ni, Cu, Zn. Answer the following:
(a) Copper has an exceptionally positive \( E^\circ_{\text{M}^{2+}/\text{M}} \) value, why?
The graph between variation of resistance of a wire as a function of its diameter keeping other parameters like length and temperature constant is
While determining the coefficient of viscosity of the given liquid, a spherical steel ball sinks by a distance \( x = 0.8 \, \text{m} \). The radius of the ball is \( 2.5 \times 10^{-3} \, \text{m} \). The time taken by the ball to sink in three trials are tabulated as shown: