Question:
Consider the concentration cell
\[
\text{Pt} | \text{H}_2 (1 \, \text{bar}) | \text{HCl} (a_1) || \text{HCl} (a_2) | \text{H}_2 (1 \, \text{bar}) | \text{Pt}
\]
In concentration cells, the magnitude of liquid junction potential depends upon the transport number of cations and anions. For cells with \( a_2^+ \text{HCl} > a_1^+ \text{HCl} \), then the value of \( E_{ij} \) is negative when:
Consider the concentration cell
\[
\text{Pt} | \text{H}_2 (1 \, \text{bar}) | \text{HCl} (a_1) || \text{HCl} (a_2) | \text{H}_2 (1 \, \text{bar}) | \text{Pt}
\]
In concentration cells, the magnitude of liquid junction potential depends upon the transport number of cations and anions. For cells with \( a_2^+ \text{HCl} > a_1^+ \text{HCl} \), then the value of \( E_{ij} \) is negative when:
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In concentration cells, the liquid junction potential becomes negative when the transport number of the cation is less than that of the anion.
Updated On: Sep 24, 2025
- \( t_+ > t_- \)
- \( t_+ < t_- \)
- \( t_+ = t_- \)
- \( t_+ = 0 \)
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The Correct Option is B
Solution and Explanation
In a concentration cell, the liquid junction potential depends on the difference in the transport numbers of cations and anions. The transport number is a measure of the fraction of the total current carried by each ion. When \( a_2^+ \text{HCl} > a_1^+ \text{HCl} \), the transport number for the cation (hydrogen ion) in the second half of the cell is higher, leading to a negative \( E_{ij} \) value when the transport number of the cation is less than that of the anion, i.e., \( t_+ < t_- \). Final Answer: \[ \boxed{t_+ < t_-} \]
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