Consider the circuit shown in the figure. Find the charge on capacitor C between A and D in a steady state.
Consider the circuit shown in the figure. Find the charge on capacitor C between A and D in a steady state.
\(C_\epsilon\)
\(\frac{C_\epsilon}{2}\)
\(\frac{C_\epsilon}{3}\)
zero
The Correct Option is D
Solution and Explanation
The correct answer is d. Zero
Explanation: A capacitor blocks the DC steady state i.e. a capacitor behaves as an open circuit in a steady state. Hence no current will flow through the capacitor. Therefore, the potential difference between A and D is, V = 0
The capacitance of a capacitor is given by, C = qV
⇒ C = 0
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