Consider a volume integral \(I=\int_V\nabla^2(\frac{1}{r})dv\) over a volume \( V \), where \( r = \sqrt{x^2 + y^2 + z^2} \). Which of the following statements is/are correct?
\( I = 0 \), if \( r = 0 \) is not inside the volume \( V \).
The integrand diverges as \( r \rightarrow \infty \).
Hide Solution
Verified By Collegedunia
The Correct Option isA, B, C
Solution and Explanation
The correct options are (A) :\( I = -4\pi \), if \( r = 0 \) is inside the volume \( V \).(B):The integrand vanishes for \( r \neq 0 \).(C):\( I = 0 \), if \( r = 0 \) is not inside the volume \( V \).