Step 1: Use the given information to find the side length of the square.
In a square, the diagonals are equal in length, and they bisect each other at right angles. Let \( s \) be the side length of the square. Using the Pythagorean theorem for the right triangle formed by two sides of the square and the diagonal, we have:
\[ \text{Diagonal}^2 = s^2 + s^2 \] Since the length of the diagonal AC is given as 50 meters: \[ 50^2 = 2s^2 \quad \Rightarrow \quad 2500 = 2s^2 \quad \Rightarrow \quad s^2 = 1250 \] \[ s = \sqrt{1250} = 35.36 \, \text{meters} \quad (\text{rounded to two decimal places}). \]
Step 2: Find the area of the square.
The area \( A \) of the square is given by: \[ A = s^2 = 1250 \, \text{square meters}. \]
Step 3: Calculate the total cost of laying grass.
The cost of laying grass is Rs. 5 per square meter. So, the total cost is: \[ \text{Total cost} = 1250 \times 5 = 6250 \, \text{Rs}. \]
Step 4: Final answer.
The total cost for laying grass in the field ABCD is Rs. 6250.00.
In the given figure, the numbers associated with the rectangle, triangle, and ellipse are 1, 2, and 3, respectively. Which one among the given options is the most appropriate combination of \( P \), \( Q \), and \( R \)?

The 12 musical notes are given as \( C, C^\#, D, D^\#, E, F, F^\#, G, G^\#, A, A^\#, B \). Frequency of each note is \( \sqrt[12]{2} \) times the frequency of the previous note. If the frequency of the note C is 130.8 Hz, then the ratio of frequencies of notes F# and C is:
Here are two analogous groups, Group-I and Group-II, that list words in their decreasing order of intensity. Identify the missing word in Group-II.
Abuse \( \rightarrow \) Insult \( \rightarrow \) Ridicule
__________ \( \rightarrow \) Praise \( \rightarrow \) Appreciate