Step 1: Use the given information to find the side length of the square.
In a square, the diagonals are equal in length, and they bisect each other at right angles. Let \( s \) be the side length of the square. Using the Pythagorean theorem for the right triangle formed by two sides of the square and the diagonal, we have:
\[ \text{Diagonal}^2 = s^2 + s^2 \] Since the length of the diagonal AC is given as 50 meters: \[ 50^2 = 2s^2 \quad \Rightarrow \quad 2500 = 2s^2 \quad \Rightarrow \quad s^2 = 1250 \] \[ s = \sqrt{1250} = 35.36 \, \text{meters} \quad (\text{rounded to two decimal places}). \]
Step 2: Find the area of the square.
The area \( A \) of the square is given by: \[ A = s^2 = 1250 \, \text{square meters}. \]
Step 3: Calculate the total cost of laying grass.
The cost of laying grass is Rs. 5 per square meter. So, the total cost is: \[ \text{Total cost} = 1250 \times 5 = 6250 \, \text{Rs}. \]
Step 4: Final answer.
The total cost for laying grass in the field ABCD is Rs. 6250.00.
Two players \( A \) and \( B \) are playing a game. Player \( A \) has two available actions \( a_1 \) and \( a_2 \). Player \( B \) has two available actions \( b_1 \) and \( b_2 \). The payoff matrix arising from their actions is presented below:
Let \( p \) be the probability that player \( A \) plays action \( a_1 \) in the mixed strategy Nash equilibrium of the game.
Then the value of p is ________ (round off to one decimal place).
The installation cost (IC) of a solar power plant is INR 89,000. The plant shall be operational for 5 years. The recurring costs for maintenance of the solar plant per year is INR 5,000 but the benefits it creates including reduction in emissions amounts to INR 25,000 per year. These are the only costs and benefits associated with this project. The social discount rate (r) considered is 4% per year. The yearwise information is presented below.