Question:
Condiser the nuclear fission ${Ne^{20} -> 2 He^{4} + C^{12}} $
Given that the binding energy/nucleon of ${Ne^{20}, He^{4}}$ and ${C^{12}}$ are, respectively, 8.03 MeV, 7.07 MeV and 7.86 MeV, identify the correct statement :
Condiser the nuclear fission ${Ne^{20} -> 2 He^{4} + C^{12}} $
Given that the binding energy/nucleon of ${Ne^{20}, He^{4}}$ and ${C^{12}}$ are, respectively, 8.03 MeV, 7.07 MeV and 7.86 MeV, identify the correct statement :
Updated On: Sep 27, 2024
- 8.3 MeV energy will be released
- energy of 12.4 MeV will be supplied
- energy of 11.9 MeV has to be supplied
- energy of 3.6 MeV will be released
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The Correct Option is C
Solution and Explanation
${Ne^{20} -> 2He^{4} + C^{12}}$
$8.30 \times 20 \; \; \; \; 2\times 7.07 \times 4 + 7.86 \times 12$
$\therefore \; E_B = (BE)_{react} - (BE)_{product} = 9.72 \, MeV$
$8.30 \times 20 \; \; \; \; 2\times 7.07 \times 4 + 7.86 \times 12$
$\therefore \; E_B = (BE)_{react} - (BE)_{product} = 9.72 \, MeV$
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