Question:

Complete the following table: 

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When converting from common names to IUPAC names: - Ethylene is an alkene, so its IUPAC name is "Ethene." - Acetylene is an alkyne, so its IUPAC name is "Ethyne." - Acetic acid is a carboxylic acid, so its IUPAC name is "Ethanoic acid." - Methyl alcohol is a simple alcohol, so its IUPAC name is "Methanol." - Acetone is a ketone, and its IUPAC name is "Propane-2-one."
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Solution and Explanation

  • 1. Ethylene: The IUPAC name of Ethylene (\(\text{CH}_2 = \text{CH}_2\)) is Ethene. It is an alkene with two carbon atoms and a double bond between them.
  • 2. Acetylene: The IUPAC name of Acetylene (\(\text{CH}_\text{≡}\text{CH}\)) is Ethyne. It is an alkyne with a triple bond between two carbon atoms.
  • 3. Acetic acid: The IUPAC name of Acetic acid (\(\text{CH}_3 - \text{COOH}\)) is Ethanoic acid. It is a carboxylic acid with two carbon atoms.
  • 4. Methyl alcohol: The IUPAC name of Methyl alcohol (\(\text{CH}_3 - \text{OH}\)) is Methanol. It is the simplest alcohol, with one carbon atom and a hydroxyl group (-OH).
  • 5. Acetone: The IUPAC name of Acetone (\(\text{CH}_3 - \text{CO} - \text{CH}_3\)) is Propane-2-one. It is a ketone with three carbon atoms and a carbonyl group (C=O) attached to the second carbon.
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