Question

Column A:
The average of √0.49 , \(\frac{3}{4}\) ,and 0.8.
Column B:
75\(\%\)
This question consists of two quantities, one in column A and other in column B. Compare the both quantities and choose answer option as

• A. if the quantity in Column B is greater
• B. if the quantity in Column A is greater
• C. if the two quantities are equal
• D. if the relationship cannot be determined from the information given

Answer 1

The Correct Option is C

To find the average of \(\sqrt{0.49}​, \frac{3}{4}​,\) and 0.8:
Calculate \(\sqrt{0.49}​:\)
\(\sqrt{0.49} = \sqrt{\frac{49}{100}} = \frac{7}{10} = 0.7\)
Convert \(\frac{3}{4}\)​ to decimal:
\(\frac{3}{4} = 0.75\)
Now, calculate the average:
\(\text{Average} = \frac{0.7 + 0.75 + 0.8}{3} = \frac{2.25}{3} = 0.75\)
Column B represents \(75\%\), which is also 0.75.
Conclusion:
Both quantities are equal.
So the correct answer is Option C.