Question:
Circuit element X when connected to peak voltage of 200 volts, a peek current of 5A flows which lags behind the voltage by ℼ/2. When a circuit element Y when connected to some same the same current flows, which is in face with the voltage. Now X and Y are connected in series with same peak voltage.The RMS value of current through the circuit will be:
Circuit element X when connected to peak voltage of 200 volts, a peek current of 5A flows which lags behind the voltage by ℼ/2. When a circuit element Y when connected to some same the same current flows, which is in face with the voltage. Now X and Y are connected in series with same peak voltage.The RMS value of current through the circuit will be:
Updated On: May 16, 2024
- 5A
- 5/√2A
- 2.5A
- 5√A
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The Correct Option is C
Solution and Explanation
The correct answer is (C): 2.5A
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