चौकटी पूर्ण करा :
कर्मवीरांचा मार्ग गतीशी दिला.
चौकटी पूर्ण करा :
कर्मवीरांचा मार्ग गतीशी दिला.
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Solution and Explanation
Step 1: Understanding the context.
या गद्यांशात कर्मवीरांबद्दल सांगितले आहे की ते त्यांच्या कार्याची योग्य दिशा आणि गती देऊन, समाजातील ताणतणावाचा सामना करतात. त्यांच्या कष्टाने समाजात सुधारणा घडवली आहे.
Step 2: Explanation.
कर्मवीर हे समाजासाठी महत्त्वपूर्ण कार्य करत असतात. ते समाजातील असमानता आणि अन्याय यावर लढत असतात, आणि त्याच वेळी त्यांनी चालवलेल्या कार्यप्रणालीच्या गतीवर परिणाम होतो.
Conclusion.
कर्मवीरांचा मार्ग समाजात एक नवीन दिशा देतो, ज्यामुळे अनेकांचे जीवन सुधारते आणि ते एक अद्वितीय मार्गदर्शक बनतात.
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- Appreciation of the poem:
Read the following poem and write an appreciation of it with the help of the points given below:
Stopping by Woods on a Snowy Evening
Whose woods these are I think I know.
His house is in the village, though;
He will not see me stopping here
To watch his woods fill up with snow
My little horse must think it queer
To stop without a farmhouse near
Between the woods and frozen lake
The darkest evening of the year.
He gives his harness bells a shake
To ask if there is some mistake.
The only other sound’s the sweep
Of easy wind and downy flake.
The woods are lovely, dark and deep,
But I have promises to keep,
And miles to go before I sleep,
And miles to go before I sleep.
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- Pick out the infinitive from the following sentence :
He was asking to go for the concert.- Maharashtra Class X Board - 2025
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- Out of the following which is a Pythagorean triplet ?
In the following figure \(\triangle\) ABC, B-D-C and BD = 7, BC = 20, then find \(\frac{A(\triangle ABD)}{A(\triangle ABC)}\).
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- Properties of Triangles
The radius of a circle with centre 'P' is 10 cm. If chord AB of the circle subtends a right angle at P, find area of minor sector by using the following activity. (\(\pi = 3.14\))
Activity :
r = 10 cm, \(\theta\) = 90\(^\circ\), \(\pi\) = 3.14.
A(P-AXB) = \(\frac{\theta}{360} \times \boxed{\phantom{\pi r^2}}\) = \(\frac{\boxed{\phantom{90}}}{360} \times 3.14 \times 10^2\) = \(\frac{1}{4} \times \boxed{\phantom{314}}\) <br>
A(P-AXB) = \(\boxed{\phantom{78.5}}\) sq. cm.