- Use the ideal gas law: \( PV = nRT \).
- Given: Mass of \( \text{CO}_2 \) = 4.4 g, molar mass = 44 g/mol, \( P = 1 \, \text{atm} \), \( T = 27^\circ\text{C} = 27 + 273 = 300 \, \text{K} \), \( R = 0.0821 \, \text{L-atm/mol-K} \).
- Moles of \( \text{CO}_2 \):
\[
n = \frac{\text{mass}}{\text{molar mass}} = \frac{4.4}{44} = 0.1 \, \text{mol}
\]
- Solve for volume \( V \):
\[
V = \frac{nRT}{P} = \frac{0.1 \times 0.0821 \times 300}{1} = 0.1 \times 0.0821 \times 300 = 2.463 \, \text{L}
\]