Question

Calculate the normality of a solution prepared by dissolving 325 g of anhydrous sodium carbonate (\( Na_2CO_3 \)) in 250 mL of water. Equivalent weight of \( Na_2CO_3 \) is 5

Hint:

Normality is the number of gram-equivalents of solute per liter of solution.

Answer 1

Moles of \( Na_2CO_3 \): \[ \text{Moles} = \frac{\text{Mass}}{\text{Equivalent weight}} = \frac{1.325}{53} = 0.025 \, \text{mol}. \] Normality: \[ \text{Normality} = \frac{\text{Moles}}{\text{Volume (in L)}} = \frac{0.025}{0.25} = 0.1 \, \text{N}. \]