Question

Calculate the molar conductivity for 0.5 M BaCl_2 if its conductivity at 298K is 0.01 \( \Omega^{-1} \text{cm}^{-1} \).

Hint:

Molar conductivity is calculated by dividing the conductivity of the solution by its molarity.

Answer 1

Step 1: Molar conductivity (\( \Lambda_m \)) is related to the conductivity (\( \kappa \)) and the molarity (\( C \)) by the formula: \[ \Lambda_m = \frac{\kappa}{C} \] Step 2: Given: \[ \kappa = 0.01 \, \Omega^{-1} \text{cm}^{-1}, \quad C = 0.5 \, \text{M} \] Step 3: Calculate the molar conductivity: \[ \Lambda_m = \frac{0.01}{0.5} = 0.02 \, \Omega^{-1} \text{cm}^2 \text{mol}^{-1} \] Thus, the molar conductivity is: \[ \boxed{0.02 \, \Omega^{-1} \text{cm}^2 \text{mol}^{-1}} \]