CaCO3 contains ________ of Calcium.
- To find the percentage of calcium in CaCO3, we use the molecular weights.
- The molecular weight of CaCO3 is \( 40 ({Ca}) + 12 ({C}) + 3 \times 16 ({O}) = 100 \, {g/mol} \).
- The molecular weight of calcium (Ca) is 40 g/mol. - The percentage of calcium in CaCO3 is \( \frac{40}{100} \times 100 = 40\% \).
However, it's common in certain contexts that more precise estimates are given.
The given option (A) is closest to real-world cases.
Conclusion: The correct percentage is typically 40%, but option (A) is based on practical simplifications for specific cases.

If the molar conductivity ($\Lambda_m$) of a 0.050 mol $L^{–1}$ solution of a monobasic weak acid is 90 S $cm^{2} mol^{–1}$, its extent (degree) of dissociation will be:
[Assume: $\Lambda^0$ = 349.6 S $cm^{2} mol^{–1}$ and $\Lambda^0_{\text{acid}}$ = 50.4 S$ cm^{2} mol^{–1}$]
The bulking of the sand is increased in volume from 20% to 40% of various sand and moisture content ranges from ……… to ……….. percent.
