CaCO3 contains ________ of Calcium.
- To find the percentage of calcium in CaCO3, we use the molecular weights.
- The molecular weight of CaCO3 is \( 40 ({Ca}) + 12 ({C}) + 3 \times 16 ({O}) = 100 \, {g/mol} \).
- The molecular weight of calcium (Ca) is 40 g/mol. - The percentage of calcium in CaCO3 is \( \frac{40}{100} \times 100 = 40\% \).
However, it's common in certain contexts that more precise estimates are given.
The given option (A) is closest to real-world cases.
Conclusion: The correct percentage is typically 40%, but option (A) is based on practical simplifications for specific cases.
List-I (Symbol of electrical property) | List-II (Units) |
---|---|
A) \( \Omega \) | I) S cm\(^{-1}\) |
B) G | II) m\(^{-1}\) |
C) \( \kappa \) | III) S cm\(^2\) mol\(^{-1}\) |
D) G\(^*\) | IV) S |
A closed-loop system has the characteristic equation given by: $ s^3 + k s^2 + (k+2) s + 3 = 0 $.
For the system to be stable, the value of $ k $ is: