CaCO3 contains ________ of Calcium.
- To find the percentage of calcium in CaCO3, we use the molecular weights.
- The molecular weight of CaCO3 is \( 40 ({Ca}) + 12 ({C}) + 3 \times 16 ({O}) = 100 \, {g/mol} \).
- The molecular weight of calcium (Ca) is 40 g/mol. - The percentage of calcium in CaCO3 is \( \frac{40}{100} \times 100 = 40\% \).
However, it's common in certain contexts that more precise estimates are given.
The given option (A) is closest to real-world cases.
Conclusion: The correct percentage is typically 40%, but option (A) is based on practical simplifications for specific cases.
What mass of 75% pure CaCO3 will be required to neutralize 50 ml of 0.5M HCL solution according to the following reaction? \[ {CaCO}_3 + 2{HCl} \to {CaCl}_2 + {CO}_2 + {H}_2{O} \]