Question:
$ C_6H_5 - CH = CHCHO {->[X]} C_6H_5CH = CHCH_2OH$ In the above sequence $X$ can be:
$ C_6H_5 - CH = CHCHO {->[X]} C_6H_5CH = CHCH_2OH$ In the above sequence $X$ can be:
Updated On: Jul 12, 2022
- $ {{H}_{2}}/Ni $
- $ NaB{{H}_{4}} $
- $ {{K}_{2}}C{{r}_{2}}{{O}_{7}}/{{H}^{+}} $
- both [a] and [b]
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The Correct Option is B
Solution and Explanation
$ NaB{{H}_{4}} $ and $ LiAl{{H}_{4}} $ attacks only carbonyl group and reduce it into alcohol group. They do not attack on double bond.
$\underset{\text{Cinnamic aldehyde}}{C_6H_5 - CH = CHCHO} {->[NaBH_4]} $
$\underset{\text{Cinnamic alcohol}}{C_6H_5 - CH = CH . CH_2OH}$
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Concepts Used:
Alcohols, Phenols, and Ethers
Alcohol is formed when a saturated carbon atom bonds to a hydroxyl (-OH) group. It is an organic compound that contains a hydroxyl functional group attached to a carbon atom.
Phenol is formed when the -OH group replaces the hydrogen atom in benzene. It is an organic compound in which a hydroxyl group directly attaches to an aromatic hydrocarbon.
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