Question:

By what percent the energy of a satellite has to be increased to shift it from an orbit of radius r to 3r?

Updated On: Aug 15, 2022
  • 0.223
  • 0.333
  • 0.667
  • 1
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The Correct Option is C

Solution and Explanation

Binding energy of satellite in 1st case $ {{U}_{1}}=-\left( -\frac{GMm}{r}+\frac{1}{2}\frac{GMm}{r} \right) $ $ =\frac{GMm}{2r} $ Binding energy of satellite in 2nd case $ {{U}_{2}}=-\left[ -\frac{GMm}{3r}+\frac{1}{2}\frac{GMm}{3r} \right] $ $ =\frac{GMm}{6r} $ Energy increased $ \Delta E={{U}_{1}}-{{U}_{2}} $ $ =\frac{GMm}{r}\left[ \frac{1}{2}-\frac{1}{6} \right] $ $ =\frac{GMm}{3r} $ % increase in energy $ =\frac{\Delta E}{{{U}_{1}}}\times 100 $ $ =\frac{GMm/3r}{GMm/2r}\times 100 $ $ =66.7 $%
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Concepts Used:

Gravitation

In mechanics, the universal force of attraction acting between all matter is known as Gravity, also called gravitation, . It is the weakest known force in nature.

Newton’s Law of Gravitation

According to Newton’s law of gravitation, “Every particle in the universe attracts every other particle with a force whose magnitude is,

  • F ∝ (M1M2) . . . . (1)
  • (F ∝ 1/r2) . . . . (2)

On combining equations (1) and (2) we get,

F ∝ M1M2/r2

F = G × [M1M2]/r2 . . . . (7)

Or, f(r) = GM1M2/r2

The dimension formula of G is [M-1L3T-2].