(a) Area of HKLM = 3 x 3 = 9 cm2
Area of IJGH = 1 x 2 = 2 cm2
Area of FEDG = 3 x 3 = 9 cm2
Area of ABCD = 2 x 4 = 8 cm2
Total area of the figure = 9 + 2 + 9 + 8 = 28 cm2
(b) Area of ABCD = 3 x 1 = 3 cm2
Area of BDEF = 3 x 1 = 3 cm2
Area of FGHI = 3 x 1 = 3 cm2
Total area of the figure = 3 + 3 + 3 = 9 cm2
Complete the drawing shown in Fig. 9.14 to indicate where the free ends of the two wires should be joined to make the bulb glow