Question:

By photoelectric effect, Einstein proved

Updated On: May 5, 2024
  • \(E = hν\)
  • $K.E.=\frac {1}{2}mv^2 $
  • $E=mc^2 $
  • $E= \frac {-Rhc^2}{n^2} $
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The Correct Option is A

Solution and Explanation

In 1905, Einstein realized that the photoelectric effect could be understood if the energy in light is not spread out over wave fronts but is concentrated in small packets, or photons. Each photon of light of frequency v has the energy \(hν\). Thus, Einstein's work on photoelectric effect gives support to \(E = hν\).
The energy carried by each particle of light (called quanta or photon) is dependent on the light’s frequency (\(ν\)) as shown:

\(E = hν\)

Where h = Planck’s constant = 6.6261 × 10-34 Js.
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