Question:
Broad sources are required in:
Broad sources are required in:
Show Hint
A broad source is necessary in the **Biprism experiment** but not in **Newton’s rings**.
Updated On: Mar 26, 2025
- Biprism experiment
- Newton’s ring experiment
- Both Biprism experiment and Newton’s ring experiment
- None of the three
Hide Solution
Verified By Collegedunia
The Correct Option is A
Solution and Explanation
A broad light source is required in the Biprism experiment to ensure sufficient interference fringes. In Newton’s rings, a monochromatic point source is preferable.
Was this answer helpful?
0
0
Top Questions on Optics
- An equilateral prism is made of a material of refractive index \( \sqrt{2} \). Find the angle of incidence for minimum deviation of the light ray.
- A symmetric thin biconvex lens is cut into four equal parts by two planes AB and CD as shown in the figure. If the power of the original lens is 4D, then the power of a part of the divided lens is:
- A transparent film of refractive index 2.0 is coated on a glass slab of refractive index 1.45. What is the minimum thickness of transparent film to be coated for the maximum transmission of green light of wavelength 550 nm?
- What is the relative decrease in focal length of a lens for an increase in optical power by 0.1 D from 2.5 D? ('D' stands for dioptre).
- Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion (A) : If Young’s double slit experiment is performed in an optically denser medium than air, then the consecutive fringes come closer. Reason (R) : The speed of light reduces in an optically denser medium than air while its frequency does not change. In the light of the above statements, choose the most appropriate answer from the options given below :
View More Questions
Questions Asked in BHU PET exam
- Given the Bessel function:
$$ J_0(x) = 1 - \frac{x^2}{2^2} + \frac{x^4}{2^2 \cdot 2^2} - \frac{x^6}{2^2 \cdot 2^2 \cdot 2^2} + \dots $$ The Bessel function $ J_1(x) $ is given by:- BHU PET - 2019
- Special Functions
- One solution (about $ x = 0 $ ) of the differential equation
$$ x^2 \frac{d^2 y}{dx^2} - 3x \frac{dy}{dx} + 4y = 0 $$ is $ y_1(x) = c_1x^2$ . A second linearly independent solution (with another constant $ c_2 $ ) is:- BHU PET - 2019
- Differential Equations
- What will be the change in the volume of a cube when its side becomes 10 times the original side?
- BHU PET - 2019
- Volume of Cube, Cuboid and Cylinder
- In how many ways can the letters of the word 'PERMUTATIONS' be arranged if vowels are together?
- BHU PET - 2019
- Permutations and Combinations
- The number of diagonals that can be drawn by joining the vertices of an octagon is:
- BHU PET - 2019
- Geometry
View More Questions