Question

Brewster's angle should lie between?

• A. \( 0^\circ \) to \( 45^\circ \)
• B. \( 45^\circ \) to \( 90^\circ \)
• C. \( 0^\circ \) to \( 90^\circ \)
• D. \( 0^\circ \) to \( 60^\circ \)

Hint:

Brewster's angle can be calculated using the refractive indices of the two media, and it typically lies between \( 45^\circ \) and \( 90^\circ \).

Answer 1

The Correct Option is B

Brewster's angle \( \theta_B \) is the angle of incidence at which light with a particular polarization is perfectly transmitted through a transparent dielectric surface, with no reflection. The relationship for Brewster's angle is given by: \[ \tan \theta_B = \frac{n_2}{n_1} \] Where: - \( n_1 \) is the refractive index of the first medium (usually air), - \( n_2 \) is the refractive index of the second medium. Since the refractive index of air is less than most other materials, Brewster's angle usually lies between \( 45^\circ \) and \( 90^\circ \) depending on the relative refractive indices. Thus, Brewster's angle generally lies between \( 45^\circ \) and \( 90^\circ \).