Question:

Box A has 10 green balls and 8 black balls. Box B has 9 green balls and 5 black balls.
What is the probability if one ball is drawn from each box that both balls are green?

Show Hint

To find the probability of independent events happening together, multiply their individual probabilities.
Updated On: Sep 30, 2025
  • \(\frac{19}{252}\)
  • \(\frac{5}{9}\)
  • \(\frac{10}{49}\)
  • \(\frac{5}{14}\)
  • \(\frac{9}{14}\)
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is C

Solution and Explanation

The probability of drawing a green ball from Box A is: \[ P(\text{green from A}) = \frac{10}{10 + 8} = \frac{10}{18} = \frac{5}{9} \] The probability of drawing a green ball from Box B is: \[ P(\text{green from B}) = \frac{9}{9 + 5} = \frac{9}{14} \] Now, since the two events are independent, the probability of both events happening is the product of their individual probabilities: \[ P(\text{both green}) = P(\text{green from A}) \times P(\text{green from B}) = \frac{5}{9} \times \frac{9}{14} = \frac{10}{49} \]
Final Answer: \[ \boxed{\frac{10}{49}} \]
Was this answer helpful?
0
0

Questions Asked in GRE exam

View More Questions