Question:
Boron does not form $B^{3+}$ ions whereas Al forms $Al^{3+}$ ions. This is because
Boron does not form $B^{3+}$ ions whereas Al forms $Al^{3+}$ ions. This is because
Updated On: Jul 6, 2022
- the size of B atom is smaller than that of Al
- the sum of $IE_1 + IE_2 + IE_3$ of B is much higher than that of Al
- the sum of $IE_1 + IE_2 + IE_3$ of Al is much higher than that of B
- both (a) and (b).
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The Correct Option is D
Solution and Explanation
Boron atom is smaller in size and therefore, the sum of $IE_1 + IE_2 + IE_3 (3659\, kJ\, mol^{-1})$ for B is much higher than that of $Al\, (2744\, kJ\, mol^{-1})$. Hence B does not form $B^{3+}$ ions.
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Concepts Used:
P-Block Elements
- P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
- P block elements are shiny and usually a good conductor of electricity and heat as they have a tendency to lose an electron. You will find some amazing properties of elements in a P-block element like gallium. It’s a metal that can melt in the palm of your hand. Silicon is also one of the most important metalloids of the p-block group as it is an important component of glass.
P block elements consist of:
- Group 13 Elements: Boron family
- Group 14 Elements: Carbon family
- Group 15 Elements: Nitrogen family
- Group 16 Elements: Oxygen family
- Group 17 Elements: Fluorine family
- Group 18 Elements: Neon family