Question

$BF_3 + LiAlH_4 \rightarrow X + LiF + AlF_3$. The incorrect statement about 'X' is:

• A. It is an electron deficient hydride
• B. It has a B-B bond
• C. This on heating with ammonia gives borazine
• D. On hydrolysis it gives a weak monobasic acid

Hint:

Always verify the structure and properties of reaction products through reliable sources or experimental data, especially when typical reaction outcomes are assumed in chemical equations.

Answer 1

The Correct Option is B

Step 1: Identify the product 'X'. Given the reaction, 'X' is likely a boron compound where BF3 is reduced by LiAlH4. The exact structure of 'X' might depend on the specific conditions of the reaction, but it is unlikely to be diborane as initially assumed since the incorrect statement points to the absence of a B-B bond. 
Step 2: Correct the understanding of 'X'. The reaction likely forms a complex where boron is bonded in a different configuration without B-B bonding, possibly a complex boron hydride or a coordination compound with aluminum and fluorine. 
Step 3: Evaluate the statements. 
(1) Likely True: The product is probably an electron-deficient hydride, consistent with boron's properties.
(2) False: 'X' does not have a B-B bond, making this statement incorrect.
(3) Likely True: If 'X' can react with ammonia, it might produce compounds like borazine under certain conditions, assuming it contains reactive boron-hydride units.
(4) Likely True: Hydrolysis of boron hydrides generally leads to the formation of boric acid, a weak monobasic acid.