Question:
Base strength of
(i) $h_3C \, {C} ^{\ominus} H_2$
(ii) $H_2 C= {C}^{\ominus} H$
(iii) $H-C \equiv C^{\ominus} $
is in the order of
Base strength of
(i) $h_3C \, {C} ^{\ominus} H_2$
(ii) $H_2 C= {C}^{\ominus} H$
(iii) $H-C \equiv C^{\ominus} $
is in the order of
Updated On: May 5, 2024
- (ii) > (i) > (iii)
- (iii) > (ii) > (i)
- (i) > (iii) > (ii)
- (i) > (ii) > (iii)
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The Correct Option is D
Solution and Explanation
Weaker the acid, strongest is its conjugate base.
Among alkane, alkene and alkyne, alkynes are most acidic and alkanes are least acidic, so the order of base strength is $alkane > alkene > alkyne $ or $ \, \, \, \, CH_3 \, _{C}^{\ominus}H_2 > H_2C = \, _{C}^{\ominus}H > H -C \equiv _{C}^{\ominus} $
Among alkane, alkene and alkyne, alkynes are most acidic and alkanes are least acidic, so the order of base strength is $alkane > alkene > alkyne $ or $ \, \, \, \, CH_3 \, _{C}^{\ominus}H_2 > H_2C = \, _{C}^{\ominus}H > H -C \equiv _{C}^{\ominus} $
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