Question:
At low temperature, phenol reacts with $ {Br_2}$ in $ { CS_2} $ to form
At low temperature, phenol reacts with $ {Br_2}$ in $ { CS_2} $ to form
Updated On: Jul 6, 2022
- m-bromophenol
- o- and p-bromophenol
- p-bromophenol
- 2,4,6-tribromophenol
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The Correct Option is B
Solution and Explanation
In presence of non-polar solvent $\left( C S _{2}\right)$ the ionization of phenol is suppressed. The ring is slightly activated and hence mono substitution occurs. On the other hand with $Br _{2}$ water phenol forms $2,4,6$ -tribromo phenol. In aqueous solution, phenol ionizes to give phenoxide ion. Due to the presence of negative charge on oxygen, the benzene ring is highly activated and hence the trisubstituted product is obtained
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Concepts Used:
Alcohols, Phenols, and Ethers
Alcohol is formed when a saturated carbon atom bonds to a hydroxyl (-OH) group. It is an organic compound that contains a hydroxyl functional group attached to a carbon atom.
Phenol is formed when the -OH group replaces the hydrogen atom in benzene. It is an organic compound in which a hydroxyl group directly attaches to an aromatic hydrocarbon.
Ether is formed when oxygen atom bonds to two alkyl or aryl groups. It is an organic compound that has an oxygen atom that is connected to two aryl and alkyl groups.
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