The chemical equation is,
\(BaCl_2 → Ba^{2+} + 2Cl^-\)
So,\(\ Λ_{BaCl_2}^0=Λ_{Ba^{2+}}^0+2Λ_{Cl^−}^0\)
Given that,
\(Λ_{Ba^{2+}}^0=127\ Ω^{−1}cm^2eq^{−1}\)
\(Λ_{Cl^−}^0=76\ Ω^{−1} cm^{2}eq^{−1}\)
\(Λ_{BaCl_2}^0\) \(= 127+2\times 76 = 127+152 = 279\ Ω^{−1}cm^2eq^{−1}\)
The equivalent conductance of \(BaCl_2\) at infinite dilution = \(\frac {279}{2}\) = \(139.5\ Ω^{−1}cm^2eq^{−1}\)
So, the correct option is (A): 139.5.
Identify the major product C formed in the following reaction sequence:
An electrochemical cell is a device that is used to create electrical energy through the chemical reactions which are involved in it. The electrical energy supplied to electrochemical cells is used to smooth the chemical reactions. In the electrochemical cell, the involved devices have the ability to convert the chemical energy to electrical energy or vice-versa.