Let Karan's age be \( K \) and Deepak's age be \( D \). The two given conditions are:
1. \( K \times D = 240 \)
2. \( 2D = K + 4 \)
From the second equation, solve for \( K \): \[ K = 2D - 4 \] Substitute this into the first equation: \[ (2D - 4) \times D = 240 \] Simplifying: \[ 2D^2 - 4D = 240 \] \[ 2D^2 - 4D - 240 = 0 \] Divide the equation by 2: \[ D^2 - 2D - 120 = 0 \] Now solve this quadratic equation using the quadratic formula: \[ D = \frac{-(-2) \pm \sqrt{(-2)^2 - 4(1)(-120)}}{2(1)} \] \[ D = \frac{2 \pm \sqrt{4 + 480}}{2} \] \[ D = \frac{2 \pm \sqrt{484}}{2} \] \[ D = \frac{2 \pm 22}{2} \] Thus, \( D = \frac{2 + 22}{2} = 12 \) or \( D = \frac{2 - 22}{2} = -10 \). Since age cannot be negative, we take \( D = 12 \).
Therefore, Deepak is currently 12 years old, and two years ago, he was \( 12 - 2 = 10 \) years old. Thus, the answer is \( 10 \) years.
"In order to be a teacher, one must graduate from college. All poets are poor. Some Mathematicians are poets. No college graduate is poor."
Which of the following is true?