Two vertices of the parallelogram \( ABCD \) are given as \( A(-1, 2, 1) \) and \( B(1, -2, 5) \). If the equation of the line passing through \( C \) and \( D \) is:
\[
\frac{x - 4}{1} = \frac{y + 7}{-2} = \frac{z - 8}{2},
\]
find the distance between sides \( AB \) and \( CD \). Hence, find the area of the parallelogram \( ABCD \).