Question

 At 300 K, for the reaction A → P, the ∆Ssys is 5 J K^-1 mo^l-1. What is the heat absorbed (in kJ mol^-1) by the system?

• A. 1.5
• B. 15
• C. 1500
• D. 0.6

Hint:

For entropy calculations: - Use \( q = T\Delta S \). - Ensure unit conversion: \( 1 \text{ J} = 10^{-3} \text{ kJ} \).

Answer 1

The Correct Option is A

Step 1: Using the relation between heat and entropy 
- From thermodynamics, \[ q = T \Delta S_{sys} \] where \( q \) is heat absorbed, \( T \) is temperature, and \( \Delta S \) is entropy change. 

Step 2: Substituting values \[ q = (300 K) \times (5 J K^{-1} mol^{-1}) \] \[ = 1500 J mol^{-1} \] \[ = 1.5 \text{ kJ mol}^{-1} \]