Question:

Assertion (A): Every rational function is continuous at every real number \(x\) at which it is defined.
Reason (R): Every rational function is a quotient of two polynomials.

Show Hint

For continuity of rational functions, just check where the denominator is non-zero.
Updated On: May 15, 2025
  • Both A and R are true, and R is the correct explanation of A
  • Both A and R are true, but R is not the correct explanation of A
  • A is true, but R is false
  • A is false, but R is true
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The Correct Option is A

Solution and Explanation

A rational function is defined as the ratio of two polynomials: \[ f(x) = \frac{p(x)}{q(x)} \] Polynomials are continuous everywhere, and the quotient of two continuous functions is also continuous at every point where the denominator is not zero. Therefore, a rational function is continuous at all \(x\) where it is defined (i.e., where \(q(x) \ne 0\)). So, the assertion is true. The reason correctly explains this: the structure of a rational function (being a quotient of polynomials) guarantees continuity at all defined points.
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