
Concept:
The direction of induced current in a coil is determined by Lenz’s law. According to Lenz’s law: The induced current flows in such a direction that it opposes the change in magnetic flux producing it. Key ideas used:
Approaching coils increase magnetic flux
Receding coils decrease magnetic flux
The induced current always opposes the {change} in flux, not the flux itself
Step 1: Effect of coil \(L_1\) on coil \(L_2\). The current in \(L_1\) is anticlockwise. If \(L_1\) is moved towards \(L_2\), the magnetic flux through \(L_2\) due to \(L_1\) increases. To oppose this increase, the induced current in \(L_2\) must produce a magnetic field in the opposite direction, which corresponds to a clockwise current.
Step 2: Effect of coil \(L_3\) on coil \(L_2\). The current in \(L_3\) is clockwise. If \(L_3\) is moved away from \(L_2\), the magnetic flux through \(L_2\) due to \(L_3\) decreases. To oppose the decrease in flux, the induced current in \(L_2\) must try to maintain the original flux direction, again requiring a clockwise current.
Step 3: Combine both effects. Both actions:
Moving \(L_1\) towards \(L_2\)
Moving \(L_3\) away from \(L_2\) produce induced currents in \(L_2\) in the same (clockwise) direction. Hence, this combination ensures that the current in the second coil is clockwise. \[ \boxed{\text{Correct option is (1)}} \]
A rod of mass $m$ and length $\ell$ is released from the position shown with its upper end hinged in a uniform horizontal magnetic field $B$. Find the maximum induced emf in the rod: 


$A$ and $B$ are identical point masses. $A$ is released as shown in the diagram at an angle $60^\circ$ from the vertical. Find $R$ if $B$ is able to reach point $C$ after elastic impact. 