To solve this problem, we need to calculate the total distance Arun traveled. Let's denote the one-way distance from home to the hostel as \(D\) miles.
Step 1: Calculate Time for Onward Journey
Arun's speed from home to hostel was 60 miles/hour. Therefore, the time taken for the onward journey is:
\(t_1 = \frac{D}{60}\) hours
Step 2: Calculate Time for Return Journey
For the return journey, Arun drove half the distance (i.e., \(\frac{D}{2}\) miles) at 25 miles/hour, and the remaining distance (i.e., \(\frac{D}{2}+5\) miles) at a speed of 50 miles/hour on the bypass road.
Time for the first half:
\(t_2 = \frac{D/2}{25} = \frac{D}{50}\) hours
Time for the bypass road:
\(t_3 = \frac{(D/2)+5}{50}\) hours
Total time for the return journey:
\(T_{\text{return}} = t_2 + t_3 = \frac{D}{50} + \frac{(D/2)+5}{50} = \frac{D}{50} + \frac{D}{100} + \frac{5}{50}\)
Simplifying:
\(T_{\text{return}} = \frac{2D}{100} + \frac{D}{100} + \frac{1}{10} = \frac{3D}{100} + \frac{1}{10}\)
Step 3: Use Given Information
According to the problem, the return journey took 30 minutes (or \(\frac{1}{2}\) hour) longer than the onward journey:
\(\frac{3D}{100} + \frac{1}{10} = \frac{D}{60} + \frac{1}{2}\)
Step 4: Solve the Equation
Multiply through by 300 to clear the fractions:
And simplifying:
\(9D + 30 = 5D + 150\)
\(4D = 120\)
\(D = 30 \) miles
Step 5: Calculate Total Journey
Total distance traveled equals the distance to and from the hostel, accounting for the bypass:
Total distance = \(D + \left(\frac{D}{2} + \frac{D}{2} + 5\right) = 30 + 35 = 65 \) miles
Therefore, the total distance traveled by Arun is 65 miles.