Step 1: Understand the time complexities.
- **Bubble sort (worst case)** (A): The worst-case time complexity of bubble sort is **$O(n^2)$**.
- **Deleting head node in singly linked list** (B): Deleting the head node takes **$O(1)$** time.
- **Binary search** (C): Binary search has a time complexity of **$O(\log n)$**.
- **Worst case of merge sort** (D): Merge sort has a worst-case time complexity of **$O(n \log n)$**.
Step 2: Arrange in increasing order.
From lowest to highest, the correct order is:
- **(C)** Binary search: $O(\log n)$
- **(B)** Deleting head node: $O(1)$
- **(D)** Merge sort: $O(n \log n)$
- **(A)** Bubble sort (worst case): $O(n^2)$
Step 3: Conclusion.
Thus, the correct order is **(C), (B), (D), (A)**.
In C language, mat[i][j] is equivalent to: (where mat[i][j] is a two-dimensional array)
Suppose a minimum spanning tree is to be generated for a graph whose edge weights are given below. Identify the graph which represents a valid minimum spanning tree?
\[\begin{array}{|c|c|}\hline \text{Edges through Vertex points} & \text{Weight of the corresponding Edge} \\ \hline (1,2) & 11 \\ \hline (3,6) & 14 \\ \hline (4,6) & 21 \\ \hline (2,6) & 24 \\ \hline (1,4) & 31 \\ \hline (3,5) & 36 \\ \hline \end{array}\]
Choose the correct answer from the options given below:
Match LIST-I with LIST-II
Choose the correct answer from the options given below:
Consider the following set of processes, assumed to have arrived at time 0 in the order P1, P2, P3, P4, and P5, with the given length of the CPU burst (in milliseconds) and their priority:
\[\begin{array}{|c|c|c|}\hline \text{Process} & \text{Burst Time (ms)} & \text{Priority} \\ \hline \text{P1} & 10 & 3 \\ \hline \text{P2} & 1 & 1 \\ \hline \text{P3} & 4 & 4 \\ \hline \text{P4} & 1 & 2 \\ \hline \text{P5} & 5 & 5 \\ \hline \end{array}\]
Using priority scheduling (where priority 1 denotes the highest priority and priority 5 denotes the lowest priority), find the average waiting time.