Question

Arrange the following spectral ranges in order of their increasing wavelength. 

(A) Radio 
(B) Visible 
(C) Infrared 
(D) Ultraviolet 
 

• A. (A), (B), (C), (D)
• B. (D), (B), (C), (A)
• C. (B), (A), (C)
• D. (C), (A), (B), (D)

Hint:

The wavelength increases from ultraviolet to visible to infrared to radio. Remember, shorter wavelengths correspond to higher frequencies.

Answer 1

The Correct Option is A

 

Step 1: Understanding the Electromagnetic Spectrum. 
The electromagnetic spectrum consists of various types of waves, including radio waves, visible light, infrared, and ultraviolet light. The key characteristic of these waves is their wavelength. The order of electromagnetic waves by wavelength (increasing wavelength) is: 

- Radio waves have the longest wavelength. 

- Visible light comes next, with wavelengths ranging from approximately 400 nm to 700 nm. 

- Infrared light has a longer wavelength than visible light, but shorter than microwaves. 

- Ultraviolet light has shorter wavelengths than visible light.

Step 2: Correct order of wavelengths. 
The correct order of wavelengths in increasing size (shorter to longer wavelength) is as follows: \[ \text{Ultraviolet} < \text{Visible} < \text{Infrared} < \text{Radio} \] Thus, the increasing order of wavelength is: (A) Radio < (B) Visible < (C) Infrared < (D) Ultraviolet.

Step 3: Conclusion. 
The correct answer is option (1) \( (A), (B), (C), (D) \).